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Outer fabric material:  100% cotton

Care instructions:  Do not tumble dry, machine wash at 30°C, A shrinkage of up to 5% may occur, Dry cleanable, Machine wash on gentle cycle

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Collar:  Mandarin collar

Fastening:  Button

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Article number:  BP421E02C-K11

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Competition | Regulation | Litigation

Martijn van de Hel (admitted to the bar in 2001)has comprehensive experience of European and Dutch competition law.

He has advised businesses in many sectors on different forms of collaboration such as joint ventures, distribution and franchise agreements (including e-commercematters) and purchasing combinations. He also has considerable experience in leniency applications and with dawn raids and cartel investigations by the Authority for Consumers Markets (ACM) and the European Commission. He successfully assisted a tour operator and two insurers with investigations into cartel practices in the Footaction Cheap Price Mango Blazer jacket black Cheap Price 4H2v0fr
and the insurance sector . Hehas alsobeen involved in thecartel investigation of the European Commission inthe shrimp sector and the investigationby the ACM regarding the admissibility of cooperation in art dealership .He is an experienced advisor on cartel-related damage claims (follow-on claims).

Martijn played a key role in quashing the most important decision by the then Netherlands Competition Authority (ACM) in relation to the ban on the abuse of dominant positions. His experience also extends to the regulated sectors. Amongst other things, he assisted a cable operator in much-discussed proceedings in which the Independent Post and Telecommunications Authority (OPTA) attempted to regulate the cable sector.

Martijn has advised many businesses and public bodies on ONLY ONLZALA Jeans Skinny Fit black denim Outlet Sale Online Low Price 2ZxkSJjr6
and unfair competition from the government. He was amongst others involved in prejudicial proceedings at the Court of Justice on aid to the Dutch electricity sector. He has supported many companies in notifying the ACM and the European Commission of mergers or takeovers and is currently assisting collaborations between care organisations - which includes navigating the approval procedures.

Cases that Martijn has worked on recently:

Martijn has been recommended for many years in the prestigiousguides to the legal profession Legal500 and Lodis Accessories Audrey RFID Card Case Red RFID Pay With Visa 69KmN
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Clients say about him:

In 2007, Martijn was selected by his peers as the most promising competition lawyer under 30 (“ ”).

He lectures frequently at seminars and training institutes and has penned numerous articles.Martijn was a partner at Boekel De Nerée before becoming a co-founder of MaverickAdvocaten N.V. Martijn van de Hel T +31 20 238 2002 M +31 6 212 108 53 martijn.vandehel@maverick-law.com

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Proof: We want to prove that dist[F1,Q]+dist[F2,Q]==dist[F1,P]. Since Q lies on the line t, and t bisects line[P,F2], thus dist[Q,P]==dist[Q,F2]. Since Q also lies on segment[P,F1], so dist[F1,Q] + dist[Q,P] == dist[F1,P]. Combine the above equation together shows dist[F1,Q]+dist[F2,Q]==dist[F1,P]. To show that t is the tangent at Q, note that line perpendicular to t and passing Q bisects the angle[F1,Q,F2]. (detail omitted here)

Note, that the midpoint of P and F2 traces out a circle. This leads to the following theorem that the pedal of a ellipse with respect to a focus is a circle.

The pedal of a ellipse with respect to a focus is a circle, conversely, the David Tate Glorious Bone Cheap Fake Cheap 2018 Discount Popular RfAxkcWj
of a circle with respect to a point inside the circle is a ellipse. This fact can be used to draw ellipses by envelope of lines.

Ellipse can be generated as a hypotrochoid . Let the parameters of the hypotrochoid be {A,B,H}, where A is the radius of the fixed circle, B is the radius of the rolling circle, and H is the distance from the tracing point to the center of the rolling circle. If A/2 == B and H ≠ B, then it's a ellipse with semimajor axis a==B+H and semiminor axis b==Abs[B-H]. Eccentricity is then e:=c/a == Sqrt[a^2-b^2]/a == Sqrt[(B+H)^2-(B-H)^2]/(B+H)

Given A, B:=1/2 A, and e, we may want to find H such that the hypotrochoid {A,B,H} generate a ellipse with eccentricity e. This is easily solved with the above information. The solution is:

h == ( -B (-2+e^2) ± 2 B Sqrt[(1-e)*(1+e)] ) / e^2

If we let A:=1, B:=1/2, e:=8/10, we get h==1/8 or 2. Two ellipses of eccentricity 8/10 as hypotrochoids with parameters {1,1/2,1/8} and {1,1/2,2} are shown below.

Light-rays from one focus will reflect to the other focus. If the radiant point is not at a focus, the envelope of the rays formed is called caustic .

Ellipse's inversion with respect to a focus is a dimpled limacon of Pascal .

The intersection of a right circular cylinder and a plane is a ellipse. One can see this by tilting a cup or a cone shaped paper cup filled with liquid. Let r be the radius of the base circle of the cylinder, α be the angle formed by the cutting plane and the plane of the base circle of the right circular cylinder. The intersection will be a ellipse with semi-major axis r/Cos[α] and semi-minor axis r.

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